Elise:
Forty ounces of a 35% gold alloy are mixed with 62 ounces of a 20% alloy. Find the concentration of the resulting gold alloy.
1
Expert's answer
2012-07-17T08:15:38-0400
So in forty ounces there are 40*0,35 ounces of pure gold. In 62 ounces there are 62*0,2& ounces of pure gold. So resulting concentration is (40*0,35+62*0,2)/(40+62)*100%=(14+12,4)/102*100%=25,9%
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment