"z = x+iy, w=u+iv."
(a) "w=z+4 \\Rightarrow u+iv=(x+4)+iy," so "u=x+4" and "y=v" .
(i) If "|z|=3," then "\\sqrt{x^2+y^2}=3" and points "(x,y)" are situated on a circle with center (0,0) and radius 3. Next, we should make a shift of this circle on a distance of 4 along x-axis, because "u=x+4" . So for (u,v) we get a circle with center (4,0) and radius 3.
(ii) arg z if the angle between radius-vector of z and x-axis. Therefore, all (x,y) points are situated on the ray with initial point (0,0) and angle between the ray and x-axis if π/3. Strictly saying, point (0,0) doesn't belong to the ray because we can't define arg of a z=0.
We may describe this ray by the following conditions:
"x>0, \\;\\; y = x\\tan\\dfrac{\\pi}{3} = \\sqrt{3}x."
To obtain the locus of (u,v) we should shift this ray along x-axis on a distance of 4, so the initial point (4,0) also does not belong to our ray. Therefore,
"u=x+4, \\;\\; v=y = \\sqrt{3}x = \\sqrt{3}(u-4)" .
We may note, that argument of w will not be equal to π/3 in every point.
The picture of (u,v) is a kind of this sketch:
(iii) Let us determine the locus of z such as |z+4|=5.
"(x+4)^2+y^2= 5^2," so it's a circle with center in (-4,0) and radius 5. We should make a shift of this circle on a distance of 4 along x-axis, because "u=x+4," therefore (u,v) are located on circle with center in (0,0) and radius 5.
(iv) If we have an equation "y=4x" , therefore points (x,y) are situated on a straight line inclined by an angle of "\\arctan 4" to the x-axis. This line passes through (0,0), so we may say that for points z
"\\arg z = \\arctan 4 \\quad (\\mathrm{for\\, x \\ge 0})" or "\\arg z = \\pi + \\arctan 4 \\quad (\\mathrm{for\\, x \\lt 0})" .
Next, we know that "u=x+4" and "v=y," so the locus of (u,v) can be defined as
"v=y=4x=4(u-4) \\Rightarrow v = 4(u-4)." It is also an equation of a straight line and the sketch is
We may also note, that argument of w will not be equal to "\\arctan 4" in every point.
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