(a) so and .
(i) If then and points are situated on a circle with center (0,0) and radius 3. Next, we should make a shift of this circle on a distance of 4 along x-axis, because . So for (u,v) we get a circle with center (4,0) and radius 3.
(ii) arg z if the angle between radius-vector of z and x-axis. Therefore, all (x,y) points are situated on the ray with initial point (0,0) and angle between the ray and x-axis if π/3. Strictly saying, point (0,0) doesn't belong to the ray because we can't define arg of a z=0.
We may describe this ray by the following conditions:
To obtain the locus of (u,v) we should shift this ray along x-axis on a distance of 4, so the initial point (4,0) also does not belong to our ray. Therefore,
.
We may note, that argument of w will not be equal to π/3 in every point.
The picture of (u,v) is a kind of this sketch:
(iii) Let us determine the locus of z such as |z+4|=5.
so it's a circle with center in (-4,0) and radius 5. We should make a shift of this circle on a distance of 4 along x-axis, because therefore (u,v) are located on circle with center in (0,0) and radius 5.
(iv) If we have an equation , therefore points (x,y) are situated on a straight line inclined by an angle of to the x-axis. This line passes through (0,0), so we may say that for points z
or .
Next, we know that and so the locus of (u,v) can be defined as
It is also an equation of a straight line and the sketch is
We may also note, that argument of w will not be equal to in every point.
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