Question #118175
let x, y, u, v be real numbers and z, w be complex numbers such that z = x + iy,
w = u+iv. In each case, describe the locus of the point (u, v) in the Argand diagram.
(a) w = z + 4 and

(i) |z| = 3, (ii) arg z = π/3, (iii) |z + 4| = 5,
(iv) y = 4x
1
Expert's answer
2020-05-27T13:01:42-0400

z=x+iy,w=u+iv.z = x+iy, w=u+iv.

(a) w=z+4u+iv=(x+4)+iy,w=z+4 \Rightarrow u+iv=(x+4)+iy, so u=x+4u=x+4 and y=vy=v .


(i) If z=3,|z|=3, then x2+y2=3\sqrt{x^2+y^2}=3 and points (x,y)(x,y) are situated on a circle with center (0,0) and radius 3. Next, we should make a shift of this circle on a distance of 4 along x-axis, because u=x+4u=x+4 . So for (u,v) we get a circle with center (4,0) and radius 3.




(ii) arg z if the angle between radius-vector of z and x-axis. Therefore, all (x,y) points are situated on the ray with initial point (0,0) and angle between the ray and x-axis if π/3. Strictly saying, point (0,0) doesn't belong to the ray because we can't define arg of a z=0.

We may describe this ray by the following conditions:

x>0,    y=xtanπ3=3x.x>0, \;\; y = x\tan\dfrac{\pi}{3} = \sqrt{3}x.

To obtain the locus of (u,v) we should shift this ray along x-axis on a distance of 4, so the initial point (4,0) also does not belong to our ray. Therefore,

u=x+4,    v=y=3x=3(u4)u=x+4, \;\; v=y = \sqrt{3}x = \sqrt{3}(u-4) .

We may note, that argument of w will not be equal to π/3 in every point.

The picture of (u,v) is a kind of this sketch:



(iii) Let us determine the locus of z such as |z+4|=5.

(x+4)2+y2=52,(x+4)^2+y^2= 5^2, so it's a circle with center in (-4,0) and radius 5. We should make a shift of this circle on a distance of 4 along x-axis, because u=x+4,u=x+4, therefore (u,v) are located on circle with center in (0,0) and radius 5.



(iv) If we have an equation y=4xy=4x , therefore points (x,y) are situated on a straight line inclined by an angle of arctan4\arctan 4 to the x-axis. This line passes through (0,0), so we may say that for points z

argz=arctan4(forx0)\arg z = \arctan 4 \quad (\mathrm{for\, x \ge 0}) or argz=π+arctan4(forx<0)\arg z = \pi + \arctan 4 \quad (\mathrm{for\, x \lt 0}) .

Next, we know that u=x+4u=x+4 and v=y,v=y, so the locus of (u,v) can be defined as

v=y=4x=4(u4)v=4(u4).v=y=4x=4(u-4) \Rightarrow v = 4(u-4). It is also an equation of a straight line and the sketch is



We may also note, that argument of w will not be equal to arctan4\arctan 4 in every point.


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