Answers:
(a) (cosπ4+isinπ4)(cos3π4+isin3π4)=(22+i22)(−22+i22)=(cos\frac{\pi}{4}+i\sin\frac{\pi}{4})(cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})= (\frac{\sqrt{2}}{2}+i\frac{\sqrt{2}}{2})(-\frac{\sqrt{2}}{2}+i\frac{\sqrt{2}}{2})=(cos4π+isin4π)(cos43π+isin43π)=(22+i22)(−22+i22)=
=−1=-1=−1
(b)2(cosπ4+isinπ4)=2+i22(cos\frac{\pi}{4}+i\sin\frac{\pi}{4})=\sqrt{2}+i\sqrt{2}2(cos4π+isin4π)=2+i2
cosπ6+i sinπ6=32+i12cos\frac{\pi}{6}+i\,sin\frac{\pi}{6}=\frac{\sqrt{3}}{2}+i\frac{1}{2}cos6π+isin6π=23+i21
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