Question

3.Solve for z if (z−2)^2 + 16=0.

\\(\\pm 4i)

\\(2\\pm 4i)

\\(-1\\pm i)

\\(2\\pm 2i)

Answer 1

$$(z-2)^2+16=0$$

$$z-2=\pm4i$$

$$z=2\pm 4i$$