Note: Given function is g(x)=x−35x−7g(x)=\frac{x−3}{5x-7}g(x)=5x−7x−3 .
Given function is not defined when the denumerator is zero.
Denumerator is zero when 5x−7=05x-7=05x−7=0 ⟹ 5x=7 ⟹ x=75\implies 5x = 7 \implies x =\frac{7}{5}⟹5x=7⟹x=57.
Hence the given function is not defined at x=75x = \frac{7}{5}x=57.
Correct option is option (d).
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