"b_1=200\\\\\nq=1+\\frac{5}{100}=1.05\\\\\nS_n=318921.46\\\\\nS_n=\\frac{b_1(1-q^n)}{1-q}\\\\\n\\frac{200(1-1.05^n)}{1-1.05}=318921.46\\\\\n1-1.05^n=-79.73\\\\\n1.05^n=80.73\\\\\nn=\\log_{1.05}80.73\\\\\nn=90"
90 payments are necessary to pay off the loan amount assuming no deposit was made
"b_n=b_1q^{n-1}\\\\\nb_{90}=200\\cdot1.05^{89}\\\\\nb_{90}=15378"
15378 is the value of the final payment that they would make assuming no deposit was made
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