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Answer to Question #11045 in Algebra for n lakshmi
Question #11045
factorize
2x^2+2(squareroot)6xy + 3y^2
2x^2+2(squareroot)6xy + 3y^2
Expert's answer
we use (a+b)^2=a^2+2ab+b^2
2x^2+2(squareroot)6xy +
3y^2=(sqrt(2)*x)^2+2*sqrt(2)*x*sqrt(3)*y+(sqrt(3)*y)^2=use formula=(
sqrt(2)*x+sqrt(3)*y )^2
2x^2+2(squareroot)6xy +
3y^2=(sqrt(2)*x)^2+2*sqrt(2)*x*sqrt(3)*y+(sqrt(3)*y)^2=use formula=(
sqrt(2)*x+sqrt(3)*y )^2
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