Answer to Question #110211 in Algebra for julaine

Question

1. (3^2) × (2×3^5 )^(-2) × (18)^2;

2. ((2×3/9 ÷3)^(-2)^-1 * (9/4 )^(2 )×(2/5 )^(-1) )

Answer 1

1. 3² × (2 × 3⁵ )^-2 × 18² = 3² × 1/(2 × 3⁵)² × (2 × 3²)² = (3² × 2² × 3⁴)/(2² × 3¹⁰) = 1/3⁴ = 3^-4 = 1/81

2. (2×3/9 ÷3)^-2*(-1) × (9/4 )² × (2/5)^-1 = (2/9)² × (9/4)² × 5/2 = (2/9 × 9/4)² × 5/2 = (1/2)² × 5/2 = 5/8