f(x+1)=2x2+x+a−1f(x+1)=2x^2+x+a-1f(x+1)=2x2+x+a−1
f(3)f(3)f(3) will be when x=2x=2x=2
f(3)=2×22+2+a−1=9+af(3)=2\times2^2+2+a-1=9+af(3)=2×22+2+a−1=9+a
aaa can be any value, since we don't have more information
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