Nth term of an arithmetic sequence is given by (a+(n−1)d(a+(n-1)d(a+(n−1)d )
then T1=5T_1=5T1=5 which means a=5
we are given 8th term as 19
T8=195+7d=19d=2T_8=19\\5+7d=19\\d=2T8=195+7d=19d=2
We have to find 100th term
T100=a+(n−1)d=5+99×2=203T_{100}=a+(n-1)d=5+99\times2=203T100=a+(n−1)d=5+99×2=203
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