Let the width be equal to x, the length be equal to x+2. We know that area of rectangle is a product of length and width. So, we have S(area) =width *length. Now substitute the values, 48=x*(x+2) and solve the equation.
x2+2x-48=0
x2+2x+1-49=0
x+1)2-72=0
(x+1-7)(x+1+7)=0
(x-6)(x+8)=0
x-6=0 or x+8=0
X=6 x=-8, but a negative value is not possible.
Thus, the width is 6m and the length is 8m.
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