Answer to Question #108 in Algebra for John

Question #108
4x^2+y^2+64x-12y+288=0
Find the vertex, co-vertices and foci
Graph the conic
1
Expert's answer
2010-05-17T05:51:02-0400
4x^2+y^2+64x-12y+288(2x+16)^2+(y-6)^2-36-256+288=0
This is ellipse.

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