Supose, we can factorize the polynomial as the following:
pn(x)=(x−3)qn−1+b,p_n(x) = (x - 3)q_{n-1} + b,pn(x)=(x−3)qn−1+b,
where qn−1q_{n-1}qn−1 is the polinomial of lower order and bbb is the reminder.
Then, according to the initial condition:
pn(3)=0⋅qn−1+b=−2.p_n(3) = 0\cdot q_{n-1} + b = -2.\\pn(3)=0⋅qn−1+b=−2.
Thus, the reminder b=−2b = -2b=−2 when p(x) is divided by x−3.
Answer. D.
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