Since, 280=2×2××2×5×7280=2×2××2×5×7280=2×2××2×5×7
=23×5×7=2^3×5×7=23×5×7 , is a prime factorization of 280 and 7 is one of the prime factor of 280.
Hence ,7∣(23×5×7)7\mid (2^3×5×7)7∣(23×5×7)
∴ 7∣280.\therefore \ 7\mid 280.∴ 7∣280.
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