A man has Rs 100 in his hand. He should buy a plate, a glass and a spoon with this rupee.
All three must buy 100 more.
But not more than Rs. 100 or less.
You can get 5 / - per plate, 3 / - per glass and 40 spoon / - for 1 / -.
If so how many plates?
How much glass?
How much spoon is it?
Let the number of plate be x, then number of glass be denoted by y and the number of spoon be denoted by z
as price of each plate is 5 , price of each glass is 3 and price of spoon is 1
then we can write an equation that
5x+3y+z=100
then we can obtain numerous solutions
(plate,glass,spoon) such that z is divisible by 40:
(x,y,z)=(1,5,80),
(x,y,z)=(9,5,40),
(x,y,z)=(6,10,40),
(x,y,z)=(3,15,40).
Comments
Dear JAYAKUMAR.M, (x,y,z)=(19, 3, 80) would be accepted if there were 0.025 for 1 spoon, but the question describes 1 for 40 spoons. A possibility of price less than 1 was not given in the question, that is why that option of the answer was not considered in the solution.
(5 x 19 = 95) 19 Plates, (3 x 1= 3) 1 Glass & (.025 x 80 = 2) 80 spoons
Dear Prasobh, we choose solutions such that z is divisible by 40.
Dear Sreejith, the equation 5x+3y+z=100 means the cost of plates, glasses and spoons and in fact z should be divisible by 40.
Its just wrong. The cost, Rs. 1 is not for a single spoon. Its the cost of 40 spoons
How foolish answer is this? Then How will they together make 100 numbers?
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