Use factor theorem to solve these examples. At first you need to find roots of given polynomial. Let's consider 2. x3+5x2-4x-20 x3+5x2-4x-20=0 Substituting x=2 we find out that it's a root. So we need to divide x3+5x2-4x-20 by x-2 We obtain x^2+7x+10 Therefore x3+5x2-4x-20=(x-2)(x^2+7x+10) Let's factorise x^2+7x+10 x^2+7x+10=0 x=-5, x=-2 So x^2+7x+10=(x+5)(x+2) Finally we get x3+5x2-4x-20=(x-2)(x+5)(x+2)
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