Question #104593
Use Cramer’s rule to solve
x+2y+z=5
2x+2y+z=6
x+2y+3z=9
1
Expert's answer
2020-03-05T16:55:36-0500

D=121221123=6+2+42212=4D=\begin{vmatrix} 1 & 2 & 1\\ 2 & 2 & 1\\ 1 & 2 &3 \end{vmatrix}=6+2+4-2-2-12=-4

Dx=521621923=30+18+12183610=4D_x=\begin{vmatrix} 5 & 2&1 \\ 6& 2&1\\ 9&2&3 \end{vmatrix}=30+18+12-18-36-10=-4

Dy=151261193=18+18+56309=4D_y=\begin{vmatrix} 1&5&1\\2&6&1\\1&9&3 \end{vmatrix}=18+18+5-6-30-9=-4

Dz=125226129=18+20+12103612=8D_z=\begin{vmatrix} 1&2&5\\2&2&6\\1&2&9 \end{vmatrix}=18+20+12-10-36-12=-8

x=Dx/D=(4)/(4)=1;x=D_x/D=(-4)/(-4)=1;

y=Dy/D=(4)/(4)=1;y=D_y/D=(-4)/(-4)=1;

z=Dz/D=(8)/(4)=2.z=D_z/D=(-8)/(-4)=2.

Answer:

x=1;y=1;z=2.x=1; y=1; z=2.


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