As per the given question patterns starts from 5 and we have to add 2 in each term,
then the following series we obtain
5, (5+2)=7, (7+2)=9, .........
5,7,9,11,13.............
here the above series is regarded as the arithmetic progression
with a as the first term and d = a2- a1 as the common difference
so, a= first term = 5,
common difference= (7-5)= 2.
We can find any term using the formula
an= a +(n-1)d,
an=5+2(n-1),
an=3+2n,
where an= nth term of AP.
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