x3−25x2−4x+100=0x^{3}-25x^{2}-4x+100=0x3−25x2−4x+100=0 then x2(x−25)−4(x−25)=0x^{2}(x-25)-4(x-25)=0x2(x−25)−4(x−25)=0 then (x2−4)(x−25)=0(x^{2}-4)(x-25)=0(x2−4)(x−25)=0 hence x1=2,x2=−2,x3=25x_1=2,x_2=-2,x_3=25x1=2,x2=−2,x3=25
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