Question #103675
Use the Cauchy-Schwarz inequality to solve x³-25x²-4x+100=0, if we know
that all its roots are rational.
1
Expert's answer
2020-02-25T08:30:41-0500

As per the given question,

x325x24x+100=0,x^3-25x^2-4x+100=0,

Now,

x34x25x2+100=0,x^3-4x-25x^2+100=0,

x(x24)25(x24)=0,x(x^2-4)-25(x^2-4)=0,

(x24)(x25)=0,(x^2-4)(x-25)=0,

so,

x2=4x^2=4 or x=25x=25,

x=±2x=\pm2 or x=25x=25.


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Comments

Assignment Expert
16.03.20, 01:15

Cauchy-Schwarz inequality does not directly produce a solution of the problem. It just shows that x^2-4=k(x-25), where k is a constant, x^2-kx+25k-4=0. The discriminant is D=k^2-4(25k-4) and it should be a square of a rational number.

Deepak
15.03.20, 15:28

Your answer is not showing Cauchy schwarz equality

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