In the given question there are two points indicated, take them as A(2,1) and B (11,10),
so we have to find the equation of line passing through these points.
We know the general formula of equation of line passing through two point
(y-y1)= "\\frac{ y_2-y_1}{x_2-x_1} (x-x_1)"
here "x_1= 2, x_2= 11, y_1=1,y_2=10"
now put these values in the above equation,
we get
"(y-1) = \\frac{10-1}{11-2} (x-2)"
(y-1)= "\\frac{9}{9} (x-2)"
(y-1)=1(x-2)
y-1=x-2 is equation of the line, but we have to represent it in the general form
and we know that general equation of line is y= mx+c.
Here, m= slope and c= intercept,
so, we can arrange it in general form
y-1= x-2
y= x-2+1
y=x-1 is standard equation of the line.
Comments
Leave a comment