Question #100888

Consider the following system of linear equations

x + 3 y = k

4 x + h y = 8

Expert's answer

For a system of equation to have infinite many solutions,

Then,

a1a2=b1b2=c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}

Using the same equation here,

14=3h=k8\frac{1}{4}=\frac{3}{h}=\frac{k}{8} ;

Hence,h=12,k=84h=12,k=\frac{8}{4} =2=2 .




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