For a system of equation to have infinite many solutions,
Then,
a1a2=b1b2=c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}a2a1=b2b1=c2c1
Using the same equation here,
14=3h=k8\frac{1}{4}=\frac{3}{h}=\frac{k}{8}41=h3=8k ;
Hence,h=12,k=84h=12,k=\frac{8}{4}h=12,k=48 =2=2=2 .
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