1 = 100%
0.2 = 20%
Let x be a volume of 100% solution, y be a volume of 20% solution.
Then
1*x + 0.2*y = 56*0.4,
x+y=56,
1*x + 0.2*y = 22.4,
x= 56-y.
Substituting x=56-y into the first equation
1*(56-y) + 0.2*y = 22.4,
-y +0.2y = -33.6,
-0.8y = -33.6,
0.8y = 33.6,
y=42,
y= 42 L of 20% acid,
x = 56-42,
x= 14 L of 100% acid.
Answer: 14 L of 100% acid, 42 L of 20% acid.
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