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Answer to Question #10018 in Algebra for Sonny
Question #10018
a vehicle travels from A to B in 8 sec. at a constant speed of 25 mph. A second vehicle travels the distance in 8 sec. What is the distance from A to B and how fast is the second vehicle traveling ?
Expert's answer
v=25, t=8/3600=1/450 => s=vt=25/450=1/9=0.111111111.....
So, speed of
second vehicle v'=s/(8 sec)=25 mph
So, speed of
second vehicle v'=s/(8 sec)=25 mph
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#339914 on Dec 2023
#339914 on Dec 2023
Comments
v=25, t=8/3600=1/450 => s=vt=25/450=1/9 So, speed of the& second vehicle v'=s/(3 sec)=1/27 mps=1/27*3600 mph=133.3 mph
I made a mistake in my problem. I am very sorry and appreciate your help. I need to know the speed of the second vehicle. It travels the distance in 3 sec. instead of the time I gave you for car #1.
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