Is true statement over arbitrary ring: "If R is a commutative ring or a left noetherian ring, then any finitely generated artinian left R-module M has finite length."
Let R be a commutative Q-algebra generated by x1, x2, . . . with the relations xixj = 0 for all i, j. Show that R is semiprimary (that is, rad R is nilpotent, and R/rad R is semisimple), but neither artinian nor noetherian.