Answer on Question #82604 – Math – Abstract Algebra
Question
Find the smallest a that is congruent to 3412 (mod 4).
Solution
Let consider only positive numbers.
If k=1k = 1k=1, a−3412=4a - 3412 = 4a−3412=4, a=3412+4=3416a = 3412 + 4 = 3416a=3412+4=3416.
Answer: a=3416a = 3416a=3416.
Answer provided by https://www.AssignmentExpert.com
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!