If p prime and p|ab then p|a or p|b.
Let's prove, that if p|a^50, then p|a.
Actually, if p|a^50, then p|a(a^49). That means, that either p|a, either p|a^49, and then a|a(a^48) etc.
Finally we get p|a^2, so p|aa, so p|a in both cases.
Now, we know that p|a, so a=pb, and a^50=(pb)^50=(p^50)(b^50), so (p^50)|(a^50).
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