Question #44361
Calculate (2x+3)(3x+4) in Z5[x]:
1
Expert's answer
2014-07-23T09:45:42-0400
Open brackets in (2x+3)(3x+4)=6x2+8x+9x+12=6x2+17x+12. Express coefficients in this expression via multiples of 5 and remainders: 6=5*1+1, 17=5*3+2, 12=5*2+2. The given expression in Z5[x] turns into x2+2x+2. Answer: x2+2x+2.

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