If there are integers a, b, s, and t such that, the sum at+bs=1, show that GCD(a,b)=1
We have at+bs=1at+bs=1at+bs=1.
Assume that GCD(a,b)=nGCD(a,b)=nGCD(a,b)=n. Then by defenition n∣an|an∣a and i there exists m∣am|am∣a and m∣bm|bm∣b.
Since n∣an|an∣a we have n∣atn|atn∣at and n∣bsn|bsn∣bs. Hence n∣(at+bs)n|(at+bs)n∣(at+bs). This implies n∣1n|1n∣1 i.e. n=1n=1n=1.
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