Let a and b be integers. Prove that if a∣b, then an∣bn for all positive integers n.
a∣b⇒ba∈N⇒bnan=ba∈N⇒an∣bna|b\Rightarrow \frac{b}{a}\in \mathbb{N} \Rightarrow \frac{bn}{an}=\frac{b}{a}\in \mathbb{N} \Rightarrow an|bna∣b⇒ab∈N⇒anbn=ab∈N⇒an∣bn
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