Question #307665

Let S be the set of all polynomial with real coefficient ,if f, g€S, define f~g if f¹=g¹ where f¹ is the derivative of f, show that ~ is an equivalence relation. Describe the equivalence classes of S

1
Expert's answer
2022-03-08T21:48:57-0500

Since f=f,f'=f', we conclude that ff,f\sim f, and hence the relation is reflexive.

Let fg.f\sim g. Then f=g,f'=g', and hence g=f.g'=f'. We conclude that gf,g\sim f, and hence the relation is symmetric.

Let fgf\sim g and gh.g\sim h. Then f=gf'=g' and g=h.g'=h'. It follows that f=h,f'=h', and hence the relation is transitive.

Therefore, this relation is an equivalence relation.

Let us describe the equivalence classes of S.S.

It follows that

[f]={gS:gf}={gS:g=f}={gS:g=f+C,CR}={f+C:CR}[f]=\{g\in S:g\sim f\}=\{g\in S:g'=f'\} \\=\{g\in S:g=f+C,C\in \R\}=\{f+C:C\in \R\}



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