Answer to Question #278670 in Abstract Algebra for Sam

Question #278670

Define Semigroup and Monoid. Show that the set of positive Integer is a monoid for the operation

defined by aOb = max{ a,b}.



1
Expert's answer
2021-12-16T16:56:25-0500

A semigroup is a pair (S,),(S,\circ), where SS is a non-empty set and :S×SS\circ:S\times S\to S is an associative binary operation on S.S. A monoid is a semigroup (S,)(S,\circ) with identity element eSe\in S in the sence that es=se=se\circ s=s\circ e=s for any sS.s\in S.


Let us show that the set of positive Integer N\N is a monoid for the operation defined by ab=max{a,b}.a\circ b = \max\{ a,b\}.

If a,bNa,b\in \N then ab=max{a,b}N,a\circ b = \max\{ a,b\}\in\N, and hence the operation is defined on the set N.\N.

Since


a(bc)=amax{b,c}=max{a,max{b,c}}=max{a,b,c}=max{max{a,b},c}=max{ab,c}=(ab)ca\circ(b\circ c)=a\circ\max\{b, c\}=\max\{a,\max\{b, c\}\}=\max\{a,b, c\} \\=\max\{\max\{a,b\}, c\}=\max\{a\circ b, c\}=(a\circ b)\circ c


for any a,b,cN,a,b,c\in\N, we conclude that operation \circ is associative, and hence (N,)(\N,\circ) is a semigroup.


Taking into account that a1=max{a,1}=a=max{1,a}=1aa\circ 1=\max\{a,1\}=a=\max\{1,a\}=1\circ a for each aN,a\in\N, we conclude that 11 is the identity of the semigroup (N,),(\N,\circ), and consequently (N,)(\N,\circ) is a monoid.


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