Question #268941

Prove/disprove that the set of all continuous functions C[0, 1] defined from the closed unit interval into R,

together with function addition + and function multiplication · is a ring


1
Expert's answer
2021-11-22T17:23:24-0500

A ring is an integral Domain if it "has no zero divisors". i.e. if a, bRb\isin R and ab=0 then a=0 or b=0


To show that your ring is not an integral domain, you need to find two continuous functions f,g

say that are not identically zero, but are such that f(x)g(x)=0 xR.f(x)g(x)=0 \ ∀x∈R.


To prove R is not an integral domain, all you need to do is find an example of zero divisors in R

A simple example is the following: f,gR

defined as


f(x)={0(,0)x[0,)f(x) = \begin{cases} 0 &\text{x } \in (-\infin, 0)\\ x &\text{x } \in[0,\infin) \end{cases}


and


g(x)={x(,0)0[0,)g(x) = \begin{cases} -x &\text{x } \in (-\infin, 0)\\ 0 &\text{x } \in[0,\infin) \end{cases}




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