Question #26479

The operation* is defined on the set Q of rational numbers by a*b= ab+a+b,a,b belongs
to Q,then find the element of Q which does not have an inverse under*

Expert's answer

Question 1.

The operation * is defined on the set Q\mathbb{Q} of rational numbers by ab=ab+a+ba*b=ab+a+b, a,bQa,b\in\mathbb{Q}. Find the element of Q\mathbb{Q} which does not have an inverse under *.

Solution. First of all note that * is commutative and is the identity under *. Indeed,

a0=0a=a0+a+0=a.a*0=0*a=a\cdot 0+a+0=a.

Now take aQa\in\mathbb{Q} and suppose there is bQb\in\mathbb{Q} such that

ab=0ab+a+b=0b(a1)=a.a*b=0\Leftrightarrow ab+a+b=0\Leftrightarrow b(a-1)=-a.

We see that if a=1a=1, then this equality becomes 0=10=-1, which is a contradiction. So, a=1a=1 is not invertible. But if a1a\neq 1, then b=a1aQb=\frac{a}{1-a}\in\mathbb{Q} is the inverse of aa.

Answer: 1. \Box

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