Question 1.
The operation ∗ is defined on the set Q of rational numbers by a∗b=ab+a+b, a,b∈Q. Find the element of Q which does not have an inverse under ∗.
Solution. First of all note that ∗ is commutative and is the identity under ∗. Indeed,
a∗0=0∗a=a⋅0+a+0=a.
Now take a∈Q and suppose there is b∈Q such that
a∗b=0⇔ab+a+b=0⇔b(a−1)=−a.
We see that if a=1, then this equality becomes 0=−1, which is a contradiction. So, a=1 is not invertible. But if a=1, then b=1−aa∈Q is the inverse of a.
Answer: 1. □