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Answer to Question #25476 in Abstract Algebra for irfan
Question #25476
√64-√p+√q=9 find p+q
Expert's answer
√64-√p+√q=9 find p+q
-√p+√q=9-8
-√p+√q=1
Moreover p and q are natural numbers.
After Squaring we have: p+q-2*sqrt(pq)=1
Then q=9, p=4.
-√p+√q=9-8
-√p+√q=1
Moreover p and q are natural numbers.
After Squaring we have: p+q-2*sqrt(pq)=1
Then q=9, p=4.
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Comments
Dear visitor In this expression p+q-sqrt (pq) the factor 2 is missing, actually it should be p+q-2*sqrt (pq).& Thanks for correcting us!
i don't get it... because when we subst 9 and 4 to p+q-sqrt (pq) is not wqual to 1
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