Let R be a ring which acts faithfully and irreducibly on a left module V . Let v ∈ V and A be a nonzero right ideal in R. Show that A • v = 0 ⇒ v = 0.
If v is nonzero, then we must have Rv = V .Since A · (Rv)=(AR) · v = A · v =0, the faithfulness of V implies that A = 0, a
contradiction.
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