Question

2n^4-9n^2+=0

Answer 1

2n^4-9n^2=0
let t=n^2 then we have
2t^2-9t=0
we can rewrite it as
t(2t-9)=0
then t=0 or t=9/2
so, returning to initial denotations, we get n^2=0 or n^2=9/2n=0 or n=-3/sqrt(2) or n=3/sqrt(2)

Thus, the answer is n=0; +-3/sqrt(2)