Question

8y^4-4y^2=0

Answer 1

8y^4-4y^2=0Let's factor out y^2:

4*y^2 *(2y^2-1)=0
Therefore we obtain two equations y^2=0 and 2y^2-1=0
whence we get y=0 and y=-1/sqrt(2), y=1/sqrt(2)So the answer is 0; +-1/sqrt(2).