Let R = End(Vk) where V is a vector space over a division ring k. Show that all ideals of R are linearly ordered by inclusion and idempotent.
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Expert's answer
2013-01-31T08:30:46-0500
If dimk V <∞, R isa simple ring. Therefore, it suffices to treat thecase when V is infinite-dimensional. The ideals of R are linearlyordered by inclusion. To show that they are allidempotent, consider any ideal nonzero I. There exists an infinite cardinal β <dimk V such that I = {f ∈ R : dimk f(V ) < β}. For any f ∈ I, let f' ∈ R be such that f' is theidentity on the f(V ), and zero on a direct complement of f(V). Clearly, f' ∈ I, and f= f'f. Therefore, f ∈ I^2, and wehave proved that I = I^2.
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