Question #22761

Find the subring of the ring Zx Zthat is not an ideal of Zx Z
1

Expert's answer

2013-01-23T11:24:53-0500

Question 1.

Find the subring of the ring Z×Z\mathbb{Z}\times\mathbb{Z} that is not an ideal of Z×Z\mathbb{Z}\times\mathbb{Z}.

Solution. Consider the subset

D={(n,n)nZ}Z×Z.D=\{(n,n)\mid n\in\mathbb{Z}\}\subset\mathbb{Z}\times\mathbb{Z}.

It is a subring of Z×Z\mathbb{Z}\times\mathbb{Z}. Indeed, it is a subgroup of additive group of Z×Z\mathbb{Z}\times\mathbb{Z}, because

(n,n)(m,m)=(nm,nm)D(n,n)-(m,m)=(n-m,n-m)\in D

for arbitrary (n,n),(m,m)I(n,n),(m,m)\in I. Furthermore, DD is closed under multiplication:

(n,n)(m,m)=(nm,nm)D(n,n)\cdot(m,m)=(nm,nm)\in D

for all (n,n),(m,m)I(n,n),(m,m)\in I. Finally, DD contains the identity (1,1)(1,1) of Z×Z\mathbb{Z}\times\mathbb{Z}. The last fact also shows that DD cannot be an ideal of Z×Z\mathbb{Z}\times\mathbb{Z} because DZ×ZD\neq\mathbb{Z}\times\mathbb{Z}. This can be demonstrated by the following observation:

(1,1)(1,0)=(1,0)∉D,(1,1)\cdot(1,0)=(1,0)\not\in D,

while (1,1)D(1,1)\in D.

Answer: for example, D={(n,n)nZ}Z×ZD=\{(n,n)\mid n\in\mathbb{Z}\}\subset\mathbb{Z}\times\mathbb{Z}. \Box

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