Question #218159

Any two non-zero subgroups of Z are isomorphic. 


1
Expert's answer
2021-07-19T05:51:19-0400

Solution:

Yes, it is correct. Let HZH \leq \mathbb{Z} be a subgroup. If H={0}H=\{0\} then H=0ZH=0 \mathbb{Z} and we are done. Otherwise H must contain non-zero elements, some of them positive. Let n=min{k>0:kH}n=\min \{k>0: k \in H\} . Then it can be shown that H=nZH=n \mathbb{Z} . We have nHn \in H and hence obviously nZHn \mathbb{Z} \leq H , because H is closed to addition and additive inverses. For the other direction let kHk \in H . We can divide k by n with remainder. We get an expression of the form k=q n+r where q,rZ,0r<nq, r \in \mathbb{Z}, 0 \leq r<n . But then note that r=k+(q)nHr=k+(-q) n \in H . Since n is by definition the smallest positive number in H and 0r<n0 \leq r<n we have to conclude that r=0, and hence knZk \in n \mathbb{Z} . This shows that HnZH \leq n \mathbb{Z} .

If n0 then nZn \neq 0\ then\ n \mathbb{Z} is indeed isomorphic to Z\mathbb{Z} . We can define an isomorphism φ:ZnZ by knk\varphi: \mathbb{Z} \rightarrow n \mathbb{Z}\ by\ k \rightarrow n k


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