Condition:
A boy is pulling a load of 150N with a sling inclined at an angle of 30 to the horizontal. If the tension in the sling is 105N, the force tending to lift the load off the ground is
Solution:
Flift=F⊥−T⊥=F∗sin30∘=(F−T)sin30∘
Where Flift is force tending to lift the load off the ground, F⊥ is boy's force, T⊥ is tension in the sling.
Flift=(150−105)∗21=22.5N
Answer: Flift=22.5N.