Question

5(2m+3)/2-(1-2m)/3=2 [3(3+2m)-(3-m)]

Answer 1

Conditions

$$5(2m+3)/2-(1-2m)/3 = 2 \ [3(3+2m)-(3-m)]$$

Solution

$$\frac{5(2m+3)}{2} - \frac{1-2m}{3} = 2 \ [3(3+2m)-(3-m)]$$ $$\frac{30m + 45 - 2 + 4m}{6} = 2 \ [9 + 6m - 3 + m]$$ $$30m + 45 - 2 + 4m = 6(12 + 14m)$$ $$34m + 43 = 72 + 84m$$ $$-50m = 72 - 43$$ $$m = -\frac{29}{50}$$