Question

line p contains points A(0,-9) and B(-1, 2) line q is parallel to line p line r is perpendicular to line q what is the slope of line r?

Answer 1

Line p contains points A(0,-9) and B(-1, 2) line q is parallel to line p line r is perpendicular to line q what is the slope of line r?

Solution:

Let form the equation of the line p. We can use the next formula:

$$\frac {y - y _ {1}}{y _ {2} - y _ {1}} = \frac {x - x _ {1}}{x _ {2} - x _ {1}}$$ $$\frac {y + 9}{11} = \frac {x}{-1} => - y - 9 = 11x => y = - 11x - 9$$

It's known that line q is parallel to line p, so the equation of line q will be the next: $y = -11x + b$, where the b is constant.

Also it's known, that the line r is perpendicular to line q, so the equation of line r will be the next: $y = \frac{1}{11} x + c$, where c is constant.

So, we can see, that the slope of line r is 1/11

Answer: 1/11