Question #186472

give an example of a non–trivial homomorphism or explain why none exists

φ:S4 → S3

1
Expert's answer
2021-05-07T09:28:54-0400

An example could by a homomorphism that is composed by two homomorphisms:

  1. There is a homomorphism "signature" sgn:SnZ/2Z\text{sgn}: S_n \to \mathbb{Z}/2\mathbb{Z} that associates to a permutation its signature.
  2. There is an injection ι:Z/2ZSm\iota: \mathbb{Z}/2\mathbb{Z} \to S_m for any m2m\geq 2 that associates 11 to a permutation (12)\begin{pmatrix} 1 & 2 \end{pmatrix}.

Composition of these two homomorphisms works, in particular, for n=4,m=3n=4, m=3 which gives us a homomorphism ϕ:S4S3\phi: S_4 \to S_3 with ϕ(even)=id;ϕ(odd)=(12)\phi(even)=id; \phi(odd)=\begin{pmatrix} 1 & 2 \end{pmatrix}.


There exist another non-trivial homomorphism, that is more interesting because it is surjective. We can prove that K={id,(12)(34),(13)(24),(14)(23)}K=\{id, (12)(34), (13)(24), (14)(23) \} is a normal subgroup of S4S_4 and the quotient S4/KS3S_4/K \simeq S_3, so the composition of these two surjective homomorphisms is a surjective homomorphism.


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