Then x has the form a+b−7 and y has the form c+d−7 for arbitrary x and y.
If(a+b−7)(c+d−7)=1,then(a−b−7)(c−d−7)=1,so1=(a+b−7)(c+d−7)(a−b−7)(c−d−7)=1which gives1=(a2+7b2)(c2+7d2)So,b=d=0,and1=a2c2,so eithera=c=1,or,a=c=−1and these are the only units inZ−7
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