a group g is isomorphism to one of its proper subgroup then g=z is it true z=integers geoup
No, it is false.
As a counter-example we can think of a group "\\mathbb{Z}^2". It is isomorphic to the group "2\\mathbb{Z} \\times \\mathbb{Z}", as "\\mathbb{Z} \\simeq 2\\mathbb{Z}" which is a proper subgroup. At the same time "\\mathbb{Z}^2 \\nsim \\mathbb{Z}", as "\\mathbb{Z}" has one generator and "\\mathbb{Z}^2" has two of them.
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