Question #178838

a group g is isomorphism to one of its proper subgroup then g=z is it true z=integers geoup


1
Expert's answer
2021-04-15T07:27:54-0400

No, it is false.

As a counter-example we can think of a group Z2\mathbb{Z}^2. It is isomorphic to the group 2Z×Z2\mathbb{Z} \times \mathbb{Z}, as Z2Z\mathbb{Z} \simeq 2\mathbb{Z} which is a proper subgroup. At the same time Z2Z\mathbb{Z}^2 \nsim \mathbb{Z}, as Z\mathbb{Z} has one generator and Z2\mathbb{Z}^2 has two of them.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS