To construct an artinian ring RRR for which the two socles differ, take R=(QQ0Q)R = \begin{pmatrix} Q & Q \\ 0 & Q \end{pmatrix}R=(Q0QQ). For this 3-dimensional Q-algebra, we have rad R=(0Q00)R = \begin{pmatrix} 0 & Q \\ 0 & 0 \end{pmatrix}R=(00Q0), which has right annihilator (QQ00)\begin{pmatrix} Q & Q \\ 0 & 0 \end{pmatrix}(Q0Q0) and left annihilator (0Q0Q)\begin{pmatrix} 0 & Q \\ 0 & Q \end{pmatrix}(00QQ), so soc(RR)<>soc(RR)\operatorname{soc}(RR) <> \operatorname{soc}(RR)soc(RR)<>soc(RR).
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