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Answer to Question #17357 in Abstract Algebra for sanches
Question #17357
For a triangular ring T =
R M
0 S
(where M is an (R, S) - bimodule), show that rad(T) =
rad(R) M
0 rad(S)
R M
0 S
(where M is an (R, S) - bimodule), show that rad(T) =
rad(R) M
0 rad(S)
Expert's answer
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