Question #16813

Let R be a ring with center C. Show that a right ideal A of R is an ideal if: End(C(R/A)) is a commutative ring;

Expert's answer

Since SCS \supseteq C, End(S(R/A))\operatorname{End}(S(R/A)) is a subring of End(C(R/A))\operatorname{End}(C(R/A)). Therefore, we have End(C(R/A))\operatorname{End}(C(R/A)) is a commutative ring. Then C(R/A)C(R/A) can be identified with C/IC/I for some ideal II of CC. Then End(C(R/A))End(C(C/I))End(C/I(C/I))C/I\operatorname{End}(C(R/A)) \sim \operatorname{End}(C(C/I)) \sim \operatorname{End}(C/I(C/I)) \sim C/I is a commutative ring, so we have End(C(R/A))\operatorname{End}(C(R/A)) is a commutative ring. Finally, we have right ideal AA of RR is an ideal.

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