Since S⊇C, End(S(R/A)) is a subring of End(C(R/A)). Therefore, we have End(C(R/A)) is a commutative ring. Then C(R/A) can be identified with C/I for some ideal I of C. Then End(C(R/A))∼End(C(C/I))∼End(C/I(C/I))∼C/I is a commutative ring, so we have End(C(R/A)) is a commutative ring. Finally, we have right ideal A of R is an ideal.